Problem 47, Proposed by
L.E. Dickson,
Fellow in Mathematics, University of Chicago:
Prove that (-1)(-1) = +1. Solutions: I. Assuming the distributive law to hold, (-1)((+1) + (-1)), or 0, = (-1)(+1) + (-1)(-1). Assuming the commutative law, (-1)(+1) = (+1)(-1 = -1. (-1) + (-1)(-1) = 0, or (-1)(-1) = +1. [L.E. Dickson] II. (-1)(-1) means that -1 is to be taken subtractively one time. 0 - (-1) = +1. (-1)(-1) = +1. [G.B.M. Zerr] III. -1 × a = -a, -1 × (a-1) = -(a-1) = -a + 1. -1 × ((a-1)-a) = -a + 1 - (-a) = -a + 1 + a = 1. [M. Philbrick] ... VII. According to Wood's Elementary Algebra, 17th edition, we have (-5)(-3) = +15. Here -3 is to be subtracted 5 times; that is, -15 is to be subtracted. Now, subtracting -15 is the same as adding +15. Therefore, we have to add +15. Similarly, (-1)(-1) = +1. [W.I. Taylor, F.P. Matz] VIII. The case (-a)(-b) = +ab is purely conventional and consequently an assumption, which, however, does not deprive the result of its great importance to algebraic operations. [J.F.W. Scheffer] |
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Illustration by Gwynedd M. Hudson, courtesy of British Library. |